Luogu P5056【模板】插头dp

其实我觉得叫插头 dp,不如叫拼图 dp 更形象。

可以将代码中注释起来的有 exit(1) 的行取消注释,如果代码没有漏洞,则不会触发 exit(1),反之则可能触发。

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#include<bits/stdc++.h>
using namespace std;
#define int long long
const int MAXn = 12;
const int MAXm = 12;
const int MAXcntsta = 5e4;
const int MOD = 1009;

template <typename T>
inline void read(T &a) {
char c;for (c = getchar(); (c < '0' || c > '9') && c != '-'; c = getchar());bool f = c == '-';T x = f ? 0 : (c ^ '0');for (c = getchar(); c >= '0' && c <= '9'; c = getchar()) {x = x * 10 + (c ^ '0');}a = f ? -x : x;
}
template <typename T, typename ...Argv>
inline void read(T &a, Argv &...argv) {
read(a), read(argv...);
}

vector<pair<int, int>> hx[2][MOD + 10];
inline void Clear(int idx) {
for (int i = 0; i < MOD; ++i) {
hx[idx][i].clear();
}
}
inline void Add(int idx, int k, int v) {
int hxk = k % MOD;
for (auto i = begin(hx[idx][hxk]), topi = end(hx[idx][hxk]); i != topi; ++i) {
if ((*i).first == k) {
(*i).second += v;
return;
}
}
hx[idx][hxk].push_back(make_pair(k, v));
}

inline int deg(int num, int deg) {
return (num >> (deg << 1)) & 3;
}
inline int assdeg(int num, int deg, int val) {
return (num & ~(3 << (deg << 1))) | (val << (deg << 1));
}

int n, m, ans; char a[MAXn + 10][MAXm + 10];
signed main() {
read(n, m);
for (int i = 1; i <= n; ++i) {
scanf("%s", a[i] + 1);
}
int begini, beginj, endi, endj;
bool ok = 0;
for (int i = 1; i <= n; ++i) {
for (int j = 1; j <= m; ++j) {
if (a[i][j] == '.') {
begini = i, beginj = j;
ok = 1;
break;
}
}
if (ok) break;
}
ok = 0;
for (int i = n; i; --i) {
for (int j = m; j; --j) {
if (a[i][j] == '.') {
endi = i, endj = j;
ok = 1;
break;
}
}
if (ok) break;
}
for (int i = begini; i <= n; ++i) {
for (int j = (i == begini) ? beginj : 1; j <= m; ++j) {
int now = ((i - 1) * m + j) & 1, last = now ^ 1;
int x = j - 1, y = j;
if (i == begini && j == beginj) Add(last, 0, 1);
Clear(now);
for (int k = 0; k < MOD; ++k) {
if (hx[last][k].empty()) continue;
for (auto l = begin(hx[last][k]), topl = end(hx[last][k]); l != topl; ++l) {
int sta = (*l).first, val = (*l).second;
if (!val) continue;
int degx = deg(sta, x), degy = deg(sta, y);
if (a[i][j] == '*') {
if (degx == 0 && degy == 0) Add(now, sta, val);
} else {
if (degx == 0 && degy == 0) {
if (i != n && j != m) Add(now, assdeg(assdeg(sta, x, 1), y, 2), val);
} else if (degx && degy == 0) {
if (i != n) Add(now, sta, val);
if (j != m) Add(now, assdeg(assdeg(sta, x, 0), y, degx), val);
} else if (degx == 0 && degy) {
if (i != n) Add(now, assdeg(assdeg(sta, x, degy), y, 0), val);
if (j != m) Add(now, sta, val);
} else if (degx == 1 && degy == 1) {
int tmpsta = sta;
tmpsta = assdeg(assdeg(tmpsta, x, 0), y, 0);
for (int o = y + 1, cnt = 1; ; ++o) {
int dego = deg(tmpsta, o);
if (dego == 1) ++cnt;
else if (dego == 2) --cnt;
if (!cnt) {
tmpsta = assdeg(tmpsta, o, 1);
break;
}
}
Add(now, tmpsta, val);
} else if (degx == 2 && degy == 2) {
// if (i == n) exit(1);
int tmpsta = sta;
tmpsta = assdeg(assdeg(tmpsta, x, 0), y, 0);
for (int o = x - 1, cnt = 1; ; --o) {
int dego = deg(tmpsta, o);
if (dego == 1) --cnt;
else if (dego == 2) ++cnt;
if (!cnt) {
tmpsta = assdeg(tmpsta, o, 2);
break;
}
}
Add(now, tmpsta, val);
} else if (degx == 2 && degy == 1) {
// if (i == n) exit(1);
Add(now, assdeg(assdeg(sta, x, 0), y, 0), val);
} else if (i == endi && j == endj) {
if (!assdeg(assdeg(sta, x, 0), y, 0)) ans += val;
}
}
}
}
if (j == m) {
for (int k = 0; k < MOD; ++k) {
if (hx[now][k].empty()) continue;
for (auto l = begin(hx[now][k]), topl = end(hx[now][k]); l != topl; ++l) {
// if (deg((*l).first, m)) exit(1);
(*l).first <<= 2;
}
}
}
}
}
printf("%lld\n", ans);
return 0;
}